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x^x = 2^ 2048
xln(x) = 2048ln(2)
ln(x)e^(ln(x)) = 2048ln(2)
ln(x) = W(2048ln(2))
x = e^[W(2048ln(2))] = 256

Me doing my year 6 sats 😩😭🫣🤮🙀🖕🏿

its easy, just use log2 and put option and check, however if u r lil bit experienced u will only check c and d so yea d will be correct.

Find 2^2048 and rename is z

Then just put values of a,b,c,d options till you get the one that is equal to z

they're*

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Last one and i can do it easily bcz calculator is allowed in SAT … I will solve by solving 2^2048 =3.2********** and then taking x=0 and all other values and when we take 256 as x then it will satisfy the equation 😂

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bro thiss is the most trickiest?

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Bro there is an easy way to calculate tgis value x to the power of x =2²⁰⁴⁸ so 2048 last digit is 8 so 2×8 is 16 the last number is 6 thats quit easy when options are given😅

Yeah, not very efficient. You could have just realized the number needed to be a base of 2, leaving c and d. 128 is 2 to the 7. And 7 times 128 is definitely not close to 2048.

D by default. But, of course, 8 times 256 is 2048.

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It's not at all a tricky question. It just takes you less than 10 sec to solve..

2²⁰⁴⁸=2²⁽¹⁰²⁴⁾=4¹⁰²⁴=4²⁽⁵¹²⁾=16⁵¹²=16²⁽²⁵⁶⁾=256²⁵⁶.
Btw, there is a game called "2048 merge block puzzle", if you play that you can improve your knowledge in powers of two.